Respostas

2013-08-29T11:15:55-03:00
Q = m.c.t

c =  \frac{Q.m}{t}

m = 200g = 0,2 kg
Q = 3400 cal
t = 80-20 = 60º C

c = \frac{Q.m}{t} =  \frac{3400.0,2}{60} =  \frac{680}{60} = 11,33 cal/g.ºC