Respostas

2013-09-01T12:39:08-03:00
2.10^8 L DE SO2 ____ 100 L DE AR
2.10^5 ML DE SO2 ____100 000 ML DE AR
(2.10^5 ml DE SO2 / 100 000 ml DE AR) = (x/ 1000000 ml)
100000 X = 2.10^5 x 10^6
100 000 x = 2 . 10^-5 . 10^6
10^5 X = 20
X= 2 . 10^-4 ppm
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