Respostas

2013-09-02T14:29:45-03:00
F(x)=2x-3
Sim.
f(-1)=2.(-1)-3=-2-3=-5
f(0)=2.0-3=0-3=-3
f(1)=2.1-3=2-3=-1
f(2)=2.2-3=4-3=1
2013-09-02T14:29:59-03:00
 Δ =  (-2)2 - 4 x 1 x (-3)
Δ = 4 + 12
Δ = 16

x´ = - (-2) + 4/2 x 1
x´ = 6/2
x´= 3

x" = - (-2) - 4 / 2 x 1
x" = - 6 / 2
x" = -3