Respostas

2013-09-08T12:31:43-03:00
∆ = b^2 -4.a.c∆= (-2)^2 -4.1.-3∆= 4+12∆=16
x= -b ±√∆ sobre 2ax= -(-2) ±√16 / 2.1x= 2 ± 4 / 2
x1= 2-4 / 2 = -1x2= 2+4 / 2 = 3
1 5 1
∆ = b^2 -4.a.c
∆= (-2)^2 -4.1.-3
∆= 4+12∆=16
x= -b ±√∆ sobre 2a
x= -(-2) ±√16 / 2.1
x= 2 ± 4 / 2
x1= 2-4 / 2 = -1
x2= 2+4 / 2 = 3