Respostas

2013-09-11T08:05:57-03:00
A) f(0) = 0² - 5x + 6= /  0 - 5x + 6= 0 
x=  \frac{-6}{-5}
f(2)= 2² - 5x +6 / 4 - 5x +6=0 / -5x=-6 -4 / -5x= -10 /x=  \frac{-10}{5} / =-2 
f(3)= x²- 5x +6= 0 3² - 5x +6=0 / 9-5x +6=0 / -5x=-9-6 / x= - \frac{-15}{5} /x=-3
f(4)= 4²- 5x +6=0 /16-5x +6=0 / -5x= -16-6 / x= \frac{-22}{5}
10 3 10