Respostas

2013-09-14T20:27:47-03:00
\frac{(1-\frac{1}{3})}{\frac{1}{9}}+[2*(1-\frac{1}{9})]-\frac{1}{2}\\\\\frac{(\frac{3-1}{3})}{\frac{1}{9}}+[2*(\frac{9-1}{9})]-\frac{1}{2}\\\\\frac{\frac{2}{3}}{\frac{1}{9}}+[2*\frac{8}{9}]-\frac{1}{2}\\\\\frac{2}{3}*\frac{9}{1}+\frac{16}{9}-\frac{1}{2}\\\\\frac{18}{3}+\frac{16}{9}-\frac{1}{2}\ (MMC\ 3,9,2=18)\\\\\frac{6*18+2*16-9*1}{18}=>\frac{108+32-9}{18}=>\boxed{\boxed{\frac{131}{18}}}
essa aki ta certa viu
:)
vou ver a outra la :p
vlw anjo ><
nad´s :)