Respostas

2013-03-26T16:41:44-03:00

x+y+z=9  ==> 3*a = 9

x*y*z=15

 

==> 3a = 9 => a = 9/3 = 3

 

 

(a-R) + a + (a+R) = 9

::

(a^2 - R^2)a = 15

[ (3^2) - (R^2) ] *a = 15

9 - R^2 = 15/3

9 - R^2 = 5

R^2 = 9 - 5

R = 2

::

(a-R) => 3 - 2 = 1

a = 3

(a+R) => 3+2 = 5

::

S={(1, 3, 5)}

::

1 ; 3 ;5

1 1 1