Respostas

2013-03-26T17:18:24-03:00

x^2-(k+1)x+(10+k)=0

:

S=x'+ (2+2)=k+1

P=x1 *x2= 10k

:

k=8 ; x1=>3 ; x2 =>6

:

x1 + x2 =k+1= 8+1= 9

x1*x2 =3*6=10+k => k=18-10

k=8

:

{k=8}

:

 

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