Respostas

2013-09-22T19:23:33-03:00
 \frac{Tc}{5}  \frac{50-32}{9}

 \frac{Tc}{5} = \frac{18}{9}

 \frac{Tc}{5}   2

Tc=5.2
Tc= 10°c

Ti=10°c
TF=10°c (obs: faz Ti-TF= 0°c
Li=90m
 \alpha =19. 10^{-6}

ΔL= Li. \alpha .ΔT
ΔL= 90.19. 10^{-6} .0
ΔL=1710. 10^{-6+3} (obs. desloca 3 virgulas)
ΔL=1,71. 10^{-3}

Prontinho


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me add ai..quando tiver alguma duvida me pergunta srrs