Respostas

2013-04-04T15:03:55-03:00

\Delta{V}=V_o\cdot{\lambda}\cdot\Delta{\theta}

 

0,2=100\cdot{\lambda}\cdot(80-0)

 

0,2=8000{\lambda}

 

\lambda=2,5\cdot{10}^{-5}^oC^{-1}

 

Então:

 

\boxed{\beta=1,25\cdot{10}^{-5}^oC^{-1}}

 

Abraços !

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