Respostas

2013-04-05T15:37:37-03:00

Dilatação Linear:

 

\Delta{L}=L_o\cdot{\alpha}\cdot{\Delta{\theta}}

 

\Delta{L}=10\cdot{12.10^{-6}}\cdot{(20-0)}

 

\Delta{L}=10\cdot{12.10^{-6}}\cdot{20}

 

\Delta{L}=0,0024m

 

Assim:

 

L=10+0,0024=\boxed{10,0024m}