Respostas

2013-10-29T15:53:41-02:00
Urna1= 1,2,3
Urna2=1,2,3,4,5

Eventos:
(1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (2,5), (3,1), (3,2), (3,3), (3,4), (3,5) = 15 eventos.
Maiores que 4 são apenas: (1,4), (1,5), (2,3), (2,4), (2,5), (3,2), (3,3), (3,4) ,(3,5) = 9 possibilidades

 \frac{9}{15}/3= \frac{3}{5}
Resposta:  \frac{3}{5}
7 4 7