Respostas

  • Usuário do Brainly
2013-11-03T15:23:21-02:00
(x+1)(2x-1)=0
2x^{2}-x+2x-1

2x^{2}+x-1
a=2 b=1 c=-1
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

$$x=\frac{-1\pm\sqrt{(1)^2-4*2*(-1)}}{2*2}

$$x=\frac{-1\pm\sqrt{1-(-8)}}{4}

$$x=\frac{-1\pm\sqrt{9}}{4}

$$x=\frac{-1\pm3}{4}
x'= -1
x''= \frac{2}{4}

ou simplificando
x''= \frac{1}{2}

Espero ter ajudado'


1 5 1