Respostas

2013-11-08T19:01:26-02:00
2 x^{2} +6x-4x-12
2 x^{2} +2x-12 valores A)2B)2C)-12
D=(b)ao quadrado-4.a.c
D=(2)ao quadrado-4.2-12
D=4+96
D=100  a formula de bhaskara
x=-b+-raiz quadrada de Delta(100)/2.a
x=-2+-raiz de 100/2.2=
x1=-2+10/4=2
x2=-2-10/4=-3