Respostas

  • Usuário do Brainly
2013-11-12T14:31:37-02:00
 x^{2} -2x-3=0          
 a=1  b=-2  c=-3
x= \frac{2 +- \sqrt{(-2 ^{2})-4.1.-3 } }{2.1}
x= \frac{2+- \sqrt{4+12} }{2}
 x=\frac{2 +- \sqrt{16} }{2}
x= \frac{2+-4}{2}
x= \frac{2+4}{2}
x= \frac{6}{2}
x=3
x= \frac{2-4}{2}
x= \frac{-2}{2}
x=-1
V=3,-1
1 5 1
2013-11-12T16:49:32-02:00