Respostas

2013-11-12T17:00:21-02:00
Por bhaskara 

6x^2+x-1=0\\\Delta=1-4.6(-1)\\\Delta=25

x= \frac{-1\pm5}{12}  \left \{ {{x'= \frac{-1+5}{12}= \frac{4}{12}= \frac{1}{3}   } \atop {x''= \frac{-1-5}{12}= \frac{-1}{2}  }} \right.

S={1/3 ,-1/2}
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