Respostas

2013-11-15T12:19:19-02:00
F(x)= -x^2-2x-1
Δ = b² -4ac
Δ = (-2)² -4 *(-1) * (-1
)Δ = 4 -4Δ = 0
x' = (-b + √∆)/ 2a
(-(-2) + 0)/2 * (-1)
(2 + 0)/-2
2/-2= -1
x'' = (-b - √∆)/ 2a
(-(-2) - 0)/2 * (-1)
(2 - 0)/-2
2/-2= -1

f(-1)= -1^2-2.(-1)-1
f(-1)=1+2-1
f(-1)=3-2
f(-1)=1

S= {-1,1}