Respostas

2013-11-15T20:50:47-02:00
Δ = b² -4ac

Δ = (-4)² -4 *1 * (-5)Δ = 16 + 20
Δ = 36
x' = (-b + √∆)/ 2a
(-(-4) + 6)/2 * 1
(4 + 6)/2
10/2= 5
x'' = (-b - √∆)/ 2a
(-(-4) - 6)/2 * 1
(4 - 6)/2
-2/2= -1

S {5,-1}

f(5)=5^2-4.5-5
f(5)=25-25
f(5)=0   
(5,0)

f(-1)=-1^2-4.-1-5
f(-1)=1+4-5
f(-1)=5-5
f(-1)= 0
(-1,0)


2013-11-15T21:31:51-02:00