Respostas

2013-11-16T15:33:27-02:00
x² + x(x-6)=0
x² + x² - 6x = 0
2x² - 6x = 0

x(2x-6) = 0
x' = 0
2x - 6 = 0
2x = 6
x = 6/2
x" = 3

2 4 2
2013-11-16T15:33:48-02:00
x^2+x^2-6x=0
2x^2-6x=0   ( Fórmula de Bhaskara)
Δ = b² -4ac
Δ = (-6)² -4 *2 * 0
Δ = 36 0
Δ = 36
x' = (-b + √∆)/ 2a
(-(-6) + 6)/2 * 2
(6 + 6)/4
12/4= 3
x'' = (-b - √∆)/ 2a
(-(-6) - 6)/2 * 2
(6 - 6)/4
0/4= 0