Respostas

2013-04-10T23:33:22-03:00

Tanβ = √3 Tanα = (√3)/3

Tanβ = Y/h

Y = √3 * √2 = √6


Tanα = X/h

X = (√3)/3 * √2

X = √(6)/3

X + Y = (√6)/3 + √6

X + Y = (√24)/3

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2013-04-11T09:02:40-03:00

Calculando x :

 

tg30^o=\frac{x}{\sqrt{2}}

 

x=tg30^o\cdot{\sqrt{2}}

 

x=\frac{\sqrt{3}}{3}\cdot{\sqrt{2}}

 

x=\frac{\sqrt{6}}{3}

 

Calculando :

 

tg60^o=\frac{y}{\sqrt{2}}

 

y=tg60^o\cdot{\sqrt{2}}

 

y=\sqrt{3}\cdot{\sqrt{2}}

 

y=\sqrt{6}

 

Calculando x + y :

 

\frac{\sqrt{6}}{3}+\sqrt{6}

 

\boxed{\frac{4\sqrt{6}}{3}}

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