Respostas

2013-11-27T23:46:44-02:00
As cordenadas do ponto P(1/2 ; 9) onde x=1/2 e y=9
As cordenadas podem ser cauculadas pelas formulas
X=-b/2a
Y=-D/4a

Logo 1/2= -m/2*(-4)
1/2=-m/-8
-4=-m
M=4
Delta (D) = m^2+16n
Logo
9=m^2+16n/-4*-4
9= (4^2+16n)/16
9=16/16+16n/16
9=1+n
N=8
2 3 2