Respostas

2013-11-30T17:07:39-02:00
A= \int\limits^3_1 {1/x^2} \, dx=F(3) - F(1)
F(x)= \int\limits {1/x^2} \, dx=-\frac{1}{x} 
A=F(3) -F(1)
F(3)= -\frac{1}{3}
F(1)= -\frac{1}{1}=-1
A=F(3)- F(1)= -\frac{1}{3}-(-1)= \frac{2}{3}