Respostas

2013-12-01T21:21:45-02:00
T1 = 300K 
P1 = 1 atm
V1 = 10L
T2 = x 
P2 = 2 atm
V2 = 20L

 \frac{P1.V1}{T1}  =  \frac{P2.V2}{T2}

 \frac{1.10}{300} =  \frac{2.20}{x}

 \frac{10}{300} =  \frac{40}{x}

10x = 12.000

x =  \frac{12000}{10}

x = 1200 K

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