Respostas

2013-12-03T20:39:48-02:00
: (i+1)^6- (1-i)^6 = 

(i+1)² - (1-i)² =
(i² + 2i + 1) - (1 -2i +i²) =
(-1 + 2i +1) - (1-2i -1) = 
2i + 2i = 
4i
1 4 1