Respostas

2013-12-03T20:57:21-02:00
Se y=2x, sendo x=1+i/1-i, calcule (x+y)^2


1+i / 1-i * 1+i/1+i = 
1 + i +i +i² / 1 +i -i -i² =
1 + 2i -1 / 1 + 1 = 
2i / 2 =
i  (loool tudo isso pra dar i shaushua)

y = 2x
y = 2.i
y = 2i

(x+y)²(i + 2i)² = 
i² + 4i² + 4i² = 
-1 -4 -4 =
-5 -4 = 
-9
2 3 2