Respostas

2013-12-04T14:59:38-02:00
Resolvendo por Bhaskara temos:
a.x²-5x+6
Δ=(b)² -4ac
Δ=(-5)²-4 x 1 x 6
Δ=25-24
Δ=1

x'= - (-5) +1 /2
x'= 3
x''= -(-5)-1/2
x''=2

b.x²-8x+12
Δ=4
x'=6
x''=2

c.x²+2x-8
Δ=6
x'=2
x''= -4

d. x²-5x+8
Δ=√-8