Respostas

2013-12-08T11:45:16-02:00
log2 32 + log5 125+log 7 49

log2 32
2^x=2^5
x=5

log5 125
5^x=125
5^x=5^3
x=3

log7 49
7^x=49
7^x=7^2
x=2

S: 5+3+2= 10
Alternativa B.

Espero ter ajudado'
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