Respostas

2013-12-10T14:06:06-02:00
F(x) = x²-2x-3
x²-2x-3 = 0
delta = b² - 4ac
delta = (-2)² - 4.(1).(3)
delta = 4 - 12
delta = 8

Formula de Baskara :

x = -b +-  \sqrtdelta / 2a
x = -(-2) +-  \sqrt8 / 2.(1)
x' = 2 + 4 / 2
x' = 6/2  x'= 3
x'' = 2 - 4 / 2
x'' = -2 / 2  x'' = -1