Respostas

2013-12-10T21:56:24-02:00
3x² - 6x + (2k-1)=0  a=3, b=-6 e c=2k-1
delta= b²-4ac
delta=(-6)²-4(3)(2k-1)
delta=36-12(2k-1)>0
delta=36-24k+12>0
delta=-24k>-36-12
delta=-24k>-48     k<-48/-24        k<2
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