Respostas

2013-12-11T11:00:33-02:00
z² - 2z + 2 =0
Δ = (-2)² - 4.1.2
Δ = 4 - 8
Δ = -4
x = (-b+/-√Δ)/2a
x = [-(-2)+/-√-4]/2.1
x = (2+/-2i)/2
x' = (1+i)
x" = (1-i)


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