Respostas

2013-12-12T16:18:35-02:00
A soma é 2730. (2,8,32, 128, 512, 2048)
1 5 1
  • Ind
  • Ambicioso
2013-12-12T16:27:18-02:00
I) Ache a razão (Q)

Q =  \frac{ A_{2} }{ A_{1} } =  \frac{8}{2}

Q= 4 

II) S =  \frac{a1 (  Q^{n} -1) }{Q -1 }

S =  \frac{2. (4^{6} - 1) }{4-1}

S =  \frac{2 .(4096-1) }{3}

S =  \frac{2.4095}{3}

S = 1365. 2
S = 2730 

Bons estudos :D