Respostas

2013-12-13T09:40:43-02:00
X² + 3x - 2 = 0

a= 1
b= 3
c= -2

x= -b + - V b² - 4ac/ 2a

x = - ( 3) + - V 3² - 4 . 1 . - 2 / 2 . 1
x = - 3 + - V 9 + 8 / 2
x = - 3 + - V 17 / 2
x' = - 3 + V17   =     não existe raiz quadrada de 17
             2
x"= - 3 - V17 
             2
2013-12-13T09:51:20-02:00
-2+3x+x²=0 Δ=b²-4ac
Δ=(3)²-4(1)(-2)
Δ=9+8
Δ=17
√17
17/4=4,25
(4,25+4)/2=4,125
17/4,125=4,21
(4,21+4,125)2=≈4,16
4,16≈√17

X'=-3+√17/2(1)
X'=-3+4,16/2
X'=1,16/2
X'≈0,58

X''=-3-4,16/2
X''=-7,16/2
X''=-3,58


BONS ,ESTUDOS