Respostas

2013-12-13T20:01:57-02:00
Cos x = -3/5 (3º qd)
sen²x + cos²x = 1
sen²x + (-3/5)² = 1
sen²x + 9/25 = 1
sen²x = 1 - 9/25
sen²x = 16/25
sen x = √(16/25)
sen x = -4/5

tg x = sen x / cos x = (-4/5) / (-3/5) = 4/3
sec x = 1 / cos x --> sec x = 1 / (-3/5) --> sec x = -5/3
cossec x = 1 / sen x = 1 / (-4/5) = -5/4
cotg x = cos x / sen x = -3/5 / -4/5 = 3/4
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