Respostas

2013-12-14T21:48:41-02:00
X²+11x=16x-6
x²+11x-16x=-6
x²-5x=-6
x²-5x+6=0
Δ = b² -4ac
Δ = (-5)² -4 *1 * 6
Δ = 25 -24
Δ = 1
x' = (-b + √∆)/ 2a
(-(-5) + 1)/2 * 1
(5 + 1)/2
6/2= 3
x'' = (-b - √∆)/ 2a
(-(-5) - 1)/2 * 1
(5 - 1)/2
4/2= 2

S={3,2}.
1 5 1
2013-12-14T21:51:29-02:00
X²+11x-16x+6=0
x²-5x+6=0
x= 5 +- √25-4.1.6 /2.1
x=5+- 1 /2
x=5+1/2=6/2=3
x= 5-1/2= 4/2=2
S={2,3}
1 5 1