Respostas

2013-12-15T17:35:59-02:00
Log(2) = 0,3
log(3) = 0,4
log(5) = 0,7

a) log[2](50) = log(50)/log(2) = log(2*5*5)/log(2) = (log(2) + 2*log(5))/log(2) =
(0,3 + 2*0,7)/0,3 = 1,7/0,3 = 5,6666

b) log[3](45) = log(45)/log(3) = log(3²*5)/log(3) = (2*log(3) + log(5))/log(3) =
(2*0,4 + 0,7)/0,4 = 1,5/0,4 = 3,75 

c) log[8](600) = log(600)/log(8) = log(2*3*100)/log(2³) = (log(2) + log(3) + 2)/(3*log(2)) =
(0,3 + 0,4 + 2)/(3*0,3) = 2,7/0,9 = 3