Respostas

2013-12-17T00:24:12-02:00
A) Fe2O3 = [( 2 x 56) + (16 x 13)] = 160 g/mol
b) NH4NO3 = [ (2 x 14) + (1 x4) + 16 x 3)] = 80 g/mol
c) Na2CO3 = [ (23 x 2 ) + (12 x1) + (16 x 3)] = 106 g/mol
d) CO(NH2)2 = [ (12 x1) + (16 x1) + (14 x 2) + ( 1 x 4) = 60 g/mol