Respostas

2013-12-19T14:46:11-02:00
A = log[7] 7 significa:
7^A = 7
7^A = 7^1
A = 1

B = Log[76] 1 significa:
76^B = 76^0
B = 0

C = log[0,5] 8 significa:
0,5^C = 8
1/2 ^ C = 2^3
1/(2^C) = 2^3
2^-C = 2^3
-C = 3
C = -3

D = log[8] 8^-2 significa:
8^D = 8^-2
D = -2

Portanto, fica:

B^A + CD = 0^1 + -3*-2 = 0 + 6 = 6