Respostas

2014-01-05T23:00:03-02:00
\boxed{i^2=-1}

Multiplicando pelo conjugado...
 \frac{Z_2}{Z_3}= \frac{-1+2i}{1-i}. \frac{(1+i)}{(1+i)} \\\\\frac{Z_2}{Z_3}=  \frac{-1-i+2i+2i^2}{1+i-i-i^2}\\\\\frac{Z_2}{Z_3}=  \frac{-1+i+2.(-1)}{1-(-1)}  \\\\\frac{Z_2}{Z_3}=  \frac{-1-2+i}{1+1} \\\\\frac{Z_2}{Z_3}=  \frac{-3+i}{2}\\\\\boxed{\frac{Z_2}{Z_3}= - \frac{3}{2} + \frac{1}{2} i}