Respostas

2014-01-10T23:05:21-02:00
Q = m . c . ΔT

Q = calor
m = massa
c = calor específico
T = temperatura

Q = 160 . 0,010 . ( 0 - 200)

Q = - 320 cal

1 5 1
2014-01-11T12:08:53-02:00
Q=m.c.ΔT
Q=160.0,10.(0-200)
Q=-320 cal