Respostas

2014-01-17T13:07:14-02:00
(5+7i)(3-2i)= 15-10i+21i-14i²                        i²=-1
 (5+7i)(3-2i)= 15+11i-14(-1)
(5+7i)(3-2i)= 15+11i+14
(5+7i)(3-2i)=29+11i

2014-01-17T13:07:20-02:00
1. O produto (5 + 7i) (3 - 2i) vale:
i²= -1
(5+7i)(3-2i)
15-10i+21i-14i²
15-10i+21i-14(-1)
15-10i+21+i14
29+11i