Respostas

2014-01-25T21:58:24-02:00
(k+1)x²-(k+3)x+1-k=0.

(k+1).4 - (k+3).2+1-k = 0

4k+4 - 2k - 6 +1 - k = 0

2k - 2 +1 - k = 0

k -1 = 0

k = 1