Respostas

2014-01-28T14:16:05-02:00
A=2 , b = 1 e c= -3
Δ = b² -4ac
Δ = 1² -4 *2 * (-3)
Δ = 1 + 24
Δ = 25
x' = (-b + √∆)/ 2a
(-1 + 5)/2 * 2
(-1 + 5)/4
4/4
1
x'' = (-b - √∆)/ 2a
(-1 - 5)/2 * 2
(-1 - 5)/4
-6/4
-1,5

x²-3x-4=0
Δ = b² -4ac
Δ = (-3)² -4 *1 * (-4)
Δ = 9 + 16
Δ = 25
x' = (-b + √∆)/ 2a
(-(-3) + 5)/2 * 1
(3 + 5)/2
8/2
4
x'' = (-b - √∆)/ 2a
(-(-3) - 5)/2 * 1
(3 - 5)/2
-2/2-
1