Respostas

2014-01-30T22:46:57-02:00
Δ = b² -4ac
Δ = (-8)² -4 *1 * 0
Δ = 64 0
Δ = 64
x' = (-b + √∆)/ 2a
(-(-8) + 8)/2 * 1
(8 + 8)/2
16/2
8
x'' = (-b - √∆)/ 2a
(-(-8) - 8)/2 * 1
(8 - 8)/2
0/2
0

S={8,0}

1 5 1
2014-01-30T22:55:16-02:00
Olá  Keyla,

 x² -8x=0 utilizando Bhaskara, temos
a=1,b=-8 e c=0
Δ = b² -4ac
Δ = (-8)² -4 .1.  0
Δ = 64 

x1 = (-b + √∆)/ 2a
-(-8) + √64)/2 . 1
(8 + 8)  : 2
16:2=8
x1 =8

x 2= (-b - √∆)/ 2a
-(-8) -√64)/2 . 1
(8 - 8)  : 2
0   : 2
 x2 =   0

S={ 8 ,0 }
1 5 1