Respostas

2014-02-01T22:34:05-02:00
OLÁ



(X+1).(X+1); (√X +15).(√X +15);(X+3) (X+3)=
X+1).(X+1);(√X +15)²;(X+3) (X+3),
PARA SER PA;√X +15)²; É A MÉDIA DOS OUTROS DOIS

X+1).(X+1)+(X+3) (X+3)/2=(√X +15)²
 X²+X+X+1+X²+3X+3X+9/2=(√X +15)²
2X²+8X+10/2=(√X +15)²
X²+4X+5=
Δ=B²-4.A.C
Δ=16+4.1.5
Δ=16+ 20
Δ=36

X=-B+-√Δ/2.1
X1=-4+6/2
X1=1
 X2=-B-√36/2
X2=-4-6/2
X2=-10/2=-5