Respostas

2014-02-26T13:05:37-03:00
Você calcular pela formula de Baskhará 
9y^2-12y+4=0 \\ a=9 .......b=-12............c=4 \\ Delta=b^2-4ac\\Delta=(-12)^2-4*9*4=144-144=0\\
x= \frac{-b+- \sqrt{delta} }{2*a} \\x= \frac{-(-12)+- \sqrt{0} }{2*9} \\\\ x= \frac{12+-0}{18} \\\\x'= \frac{12-0}{18} = \frac{2}{3}  \\ \\ x''= \frac{12+0}{18} = \frac{2}{3}  \\
2 4 2