Respostas

2013-05-08T13:58:52-03:00

/sqrt = raiz quadrada

 

bhaskara =         -b+-\sqrt{b²-4ac}/2a

 

formula              x²+x-56=0

a=1

b=1

c=-56

 

-1+-/sqrt{(1²)-4*1*(-56)}/2*1

-1+-/sqrt{1+224}/2

-1+-/sqrt{225)/2

-1+-15/2

x¹=-1+15/2

x²=-1-15/2