Respostas

2014-03-06T20:38:21-03:00
(X-1), (x-2), (x-3), (x-4) = 24
[(X-1), (x-2)] [(x-3), (x-4)] = 24
(X ^ 2 - 3x + 2) (x ^ 2 - 7x + 12) = 24
x ^ 4-10x ^ 3 +35 x ^ 2 - 50x + 24 = 24
x ^ 4-10x ^ 3 +35 x ^ 2 - 50x = 0
x (x ^ 3 - ^ 2 + 10x 35x - 10) = 0
x (x - 5) (x ^ 2 - 5x + 2) = 0
x = 0
(X - 5) = 0
x = 5
(X ^ 2 - 5x + 2) = 0
x = [5 ± √ (5 ^ 2 - 4 (2))] / 2
x = [5 ± √ 17] / 2
Espero ter ajudado !