Respostas

  • Usuário do Brainly
2014-03-09T12:03:38-03:00
 \frac{Tc}{5}  \frac{Tf-32}{9}

Tf = 4Tc

 \frac{Tc}{5}  \frac{4Tc-32}{9}

9Tc = 20Tc - 160

9Tc - 20Tc = -160

-11Tc = -160

Tc =  \frac{-160}{-11}

Tc = 14,55 °C

14,55 
· 4 = 58,2 °F