Respostas

2013-05-10T23:52:11-03:00

O perimetro será a dAB + dBC + dCA logo:\sqrt{(1-7)^{2}+(3-3)^2} + \sqrt{(7-7)^{2}+(3-11)^2} + \sqrt{(7-1)^{2}+(11-3)^2}= \sqrt{36 + 0} + \sqrt{0 + 64} + \sqrt{36 + 64}= \sqrt{36} + \sqrt{64} + \sqrt{100}= 6 + 8 +10= 24

 

Espero ter ajudado =)