Respostas

2014-03-10T01:37:44-03:00
9x²=(x²-4x+4)+(9x²-2(3x)(3/2)+9/4)
9x²=x²+9x²-4x-18x/2-4-9/4)
9x²-9x²=x²-4x-9x+4+9/4
0=x²-13x-4-9/4 (x4 para eliminar o denominador)
0=(4x²-52x+16+9)/4
4x²-52x+25=0
Δ=b²-4ac=> Δ=52²-4(4)(25)=2074-400 =>Δ=2304
x=(-b±√Δ)/2a => x=(-(-52)±48)/2*4 =>x=(52±48)/8
x₁=(52+48)/8=100/8  x₁=25/2
x₂=(52-48)/8=4/8       x₂=1/2